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The percentage composition of CF4 is %C = 13.64% and %F = 86.36% 

The solution are as follows:
Molar mass of CF4 = 88 
molar mass of C = 12 
molar mass of F = 4x19 = 76 

% C = 12/88 x 100 = 13.64% 
% F = 76/88 x 100 = 86.36%
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Answer:

C = 13.64%

F = 86.36% 

Explanation:

Percentage composition = (mass/molar mass) x 100

Molar mass of CF4 = 88 

C = 12g/mol

F = 19g/mol

C = 12/88 x 100 = 13.64% 

F = 76/88 x 100 = 86.36%

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