Answer:
The magnitude of the given vector is [tex]\sqrt{14}[/tex]
Explanation:
For any given vector [tex]\overrightarrow{r}=x\widehat{i}+y\widehat{j}+z\widehat{k}[/tex]
The magnitude is given by
[tex]|r|=\sqrt{x^2+y^2+z^2}[/tex]
comparing with the given vector [tex]\overrightarrow{A}=1\widehat{i}-2\widehat{j}+3\widehat{k}[/tex]
we get
x = 1, y = -2, z = 3
Thus the magnitude of vector A is
[tex]|r|=\sqrt{1^2+(-2)^2+3^2}\\\\\therefore |r|=\sqrt{14}[/tex]
