gallothai gallothai
  • 21-07-2019
  • Mathematics
contestada

What is the directrix of the parabola defined by 1/4(y 3)=(x-2)^2?

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 21-07-2019

Answer:

[tex]y = - 3.0625[/tex]

Step-by-step explanation:

The given parabola has equation:

[tex] \frac{1}{4} (y + 3) = {(x - 2)}^{2} [/tex]

Or

[tex]{(x - 2)}^{2} = \frac{1}{4} (y + 3)[/tex]

We compare this to

[tex] {(x - h)}^{2} = 4p(y - k)[/tex]

[tex] \implies \: 4p = \frac{1}{4} [/tex]

[tex]p = \frac{1}{4} \div 4[/tex]

[tex]p = \frac{1}{4} \times \frac{1}{4} [/tex]

[tex]p = \frac{1}{16} [/tex]

The vertex of this parabola is (2,-3)

The directrix is p units below the y-value of the vertex

[tex]y = - 3 - \frac{1}{16} = - 3.0625[/tex]

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