Answer:
344.02 g.
Explanation:
- Knowing that the no. of moles can be calculated using the relation:
no. of moles (n) = mass/molar mass
no. of moles Al(OH)₃ = 4.41 mol & molar mass of Al(OH)₃ = 78.01 g/mol.
∴ mass = no. of moles * molar mass = (4.41 mol)*(78.01 g/mol) = 344.02 g.
