Respuesta :

r3t40

[tex]f(x)=x+1\implies\boxed{f^{-1}(x)=\frac{1}{x+1}}[/tex]

Answer:

[tex]f^{-1}[/tex](x) = x - 1

Step-by-step explanation:

Let y = f(x), that is

y = x + 1

Rearrange making x the subject

Subtract 1 from both sides

y - 1 = x ( change y back into terms of x for inverse )

x = y - 1, hence

[tex]f^{-1}[/tex](x) = x - 1