Answer:
The smallest zero is x = -3
Step-by-step explanation:
We have been given the equation [tex]h(x)=4x^2-8x-60[/tex]
In order to find the zero, h(x) = 0
[tex]4x^2-8x-60=0[/tex]
We can rewrite the equation by factor out 4
[tex]x^2-2x-15=0[/tex]
Middle term can be written as -2x = -5x+3x
[tex]x^2-5x+3x-15=0[/tex]
Now, we factored out GCF
[tex]x(x-5)+3(x-5)=0[/tex]
Factored out the common term
[tex](x-5)(x+3)=0[/tex]
Apply the zero product property
[tex](x-5)=0, (x+3)=0\\\\x=5,-3[/tex]
Hence, the smallest zero is x = -3
