garydesir1
garydesir1 garydesir1
  • 23-02-2019
  • Mathematics
contestada

Hi there!

Can I get some help with #2 and #6 Calculus? Please show your work.

thanks! ​

Hi there Can I get some help with 2 and 6 Calculus Please show your work thanks class=

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 23-02-2019

Answer:

1.  36 -24x

2.  -6x/ (3x^2+5)^2

Step-by-step explanation:

2.

y = 1 - 3u^2

dy/dx = -6u du/dx

We can find du/dx

u = 3 -2x

du/dx = -2

Substituting back in for  u and du/dx

dy/dx = -6u du/dx

dy/dx = -6 (3-2x) (-2)

dy/dx = 12 (3-2x)

         = 36 -24x

6.  y = 1/u = u ^ -1

dy/dx = -1 u^-2 du/dx

u = 3x^2 +5

du/dx = 6x

Substituting back in for  u and du/dx

dy/dx = - (3x^2+5) ^-2 (6x)

         = -6x/ (3x^2+5)^2

 

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