Hello from MrBillDoesMath!
Answer:
Choice A
Discussion:
Start by focusing on the value of y when x = 1 (point of apparent discontinuity). From the graph y = 3 when x = 1. This eliminates Choice C ( as 2x = 2, not 3, at x = 1) and Choice D (as 1/2x = 1/2, not 3, at x = 1)
Consider Choice B at x = 1/2. From the graph, y = 1 at x = 1/2 but Choice B has y = -2x = -2(1/2) = -1, not 1, at x = 1/2.
We have eliminated Choices B, C, and D so Choice A is the only remaining choice.
Thank you,
MrB
