[tex]Given : \sqrt{4q - 2} = \sqrt{3q + 8}[/tex]
Squaring on both sides we get :
⇒ 4q - 2 = 3q + 8
rearranging like terms
⇒ 4q - 3q = 8 + 2
⇒ q = 8 + 2
⇒ q = 10
Hey there!
[tex]\sqrt{4q-2} = \sqrt{3q+8}[/tex]
Square each side to get rid of the radical sign.
[tex]\sqrt{4q-2}^2= \sqrt{3q+8}^2[/tex]
Now we have:
4q-2= 3q+8
Add 2 on both sides.
4q= 3q+10
Subtract 3q on each side.
q=10
10 is your answer.
I hope this helps!
~kaikers
