jjxt126
jjxt126 jjxt126
  • 23-10-2018
  • Mathematics
contestada

3x + 7 > 4x + 2 plz solve truthfully not freeA) x > 5

B) x < 5

C) x > 9

D) x < 9






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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 23-10-2018

3x+7 > 4x+2

subtract 3x from each side

7 > x+2

subtract 2 from each side

5> x

this can also be written as x< 5


Choice B

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