kaidencearley kaidencearley

25-09-2018
Mathematics

contestada

Solve for r.

s=2πrh

2πsh=r

s2πh=r

s2=r

s2π=r

Respuesta :

27-09-2018

[tex]2\pi rh=s\ \ \ \ |:2\pi h\neq0\\\\\boxed{r=\dfrac{s}{2\pi h}}[/tex]

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