Write the equation of a line that is parallel to y=0.75x and passes through the point (8,0)

Standard form of linear eqn : y=mx+c
m= gradient
c= y intercept

Line that is parallel = Same Gradient
Eqn of 2nd Line : y=0.75x+c
Given (8,0) where x=8 and y =0,
0=(0.75)(8) + c
c = -6
Therefore y=0.75x-6

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TPS00 TPS00 · Answer 2 · 2018-09-23T05:38:31+02:00

TPS00 TPS00

23-09-2018

A line passing parallel to y = 0.75x will be of the form:

[tex]y = 0.75x + k[/tex]

where k is a constant.

It passes through (8,0)

Thus,

[tex]y = 0.75x + k \\ \\ 0 = 0.75 \times 8 + k \\ \\ 0 = 6 + k \\ \\k = - 6[/tex]

[tex]\textbf{The equation is \: \: y = 0.75x - 6} [/tex]

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