balonmic001 balonmic001

22-07-2018
Mathematics

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what are solutions to the equation below
x^2-3x+27=6x+7

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konrad509 konrad509

22-07-2018

[tex] x^2-3x+27=6x+7 \\
x^2-9x+20=0\\
x^2-5x-4x+20=0\\
x(x-5)-4(x-5)=0\\
(x-4)(x-5)=0\\
x=4 \vee x=5 [/tex]

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