hadhi556 hadhi556
  • 22-07-2018
  • Mathematics
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factorise with factor theorem: 8y^3-125x^3

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Cathenna
Cathenna Cathenna
  • 22-07-2018

[tex]\\ \\ = > 8 {y}^{3} - 125 {x}^{3} \\ \\ = > {(2y)}^{3} - {(5x)}^{3} \\ \\ = > (2y - 5x)(( {2y)}^{2} + 2x \times 5y + ( {5x)}^{2} ) \\ \\ = > (2y - 5x)(4 {y}^{2} + 10xy + 25 {y}^{2} ) \: \: \: \: \: \: \: (ans)[/tex]
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