Respuesta :

Jrdan
So the function we're dealing with is

f(x) = [tex] \frac{x+6}{x^{2}-9x+18 } [/tex]

Factorising we get, [tex]x^{2} -9x+18=0[/tex]
[tex](x-3)(x-6)=0[/tex]

Therefore, the vertical asymptotes are at x = 3 and x = 6